fix encoded patterns not showing the encoded item in AE GUIs

This commit is contained in:
PrototypeTrousers
2022-11-08 18:01:00 -03:00
parent 1f12fc5e91
commit 9abd53a8e8
+32 -1
View File
@@ -39,6 +39,7 @@ import appeng.core.sync.packets.PacketSwapSlots;
import appeng.fluids.client.render.FluidStackSizeRenderer;
import appeng.fluids.container.slots.IMEFluidSlot;
import appeng.helpers.InventoryAction;
import appeng.items.misc.ItemEncodedPattern;
import appeng.util.Platform;
import appeng.util.item.AEItemStack;
import com.google.common.base.Joiner;
@@ -897,7 +898,37 @@ public abstract class AEBaseGui extends GuiContainer implements IMTModGuiContain
}
}
if (s instanceof SlotPlayerInv || s instanceof SlotPlayerHotBar) {
super.drawSlot(s);
if (!is.isEmpty() && is.getItem() instanceof ItemEncodedPattern) {
final ItemEncodedPattern iep = (ItemEncodedPattern) is.getItem();
final ItemStack out = iep.getOutput(is);
if (!out.isEmpty()) {
AppEngSlot appEngSlot = ((AppEngSlot) s);
appEngSlot.setDisplay(true);
appEngSlot.setReturnAsSingleStack(true);
this.zLevel = 100.0F;
this.itemRender.zLevel = 100.0F;
if (!this.isPowered()) {
drawRect(s.xPos, s.yPos, 16 + s.xPos, 16 + s.yPos, 0x66111111);
}
this.zLevel = 0.0F;
this.itemRender.zLevel = 0.0F;
// Annoying but easier than trying to splice into render item
super.drawSlot(s);
if (isShiftKeyDown()) {
this.stackSizeRenderer.renderStackSize(this.fontRenderer, AEItemStack.fromItemStack(out), s.xPos, s.yPos);
} else {
super.drawSlot(s);
}
return;
}
} else {
super.drawSlot(s);
}
} else if (s instanceof AppEngSlot) {
AppEngSlot appEngSlot = ((AppEngSlot) s);
appEngSlot.setDisplay(true);