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sudo sh execute for && in commands - preventing double sudo

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This commit is contained in:
makalaaneesh
2015-12-23 14:35:47 +05:30
parent c3b1ba7637
commit f249098336
2 changed files with 6 additions and 3 deletions
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thefuck/rules/sudo.py
+4 -2
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@@ -21,7 +21,7 @@ patterns = ['permission denied',
def match(command):
if command.script_parts and command.script_parts[0] == 'sudo':
if command.script_parts and '&&' not in command.script_parts and command.script_parts[0] == 'sudo':
return False
for pattern in patterns:
@@ -32,7 +32,9 @@ def match(command):
def get_new_command(command):
if '>' in command.script:
if '&&' in command.script:
return u'sudo sh -c "{}"'.format(" ".join([part for part in command.script_parts if part != "sudo"]))
elif '>' in command.script:
return u'sudo sh -c "{}"'.format(command.script.replace('"', '\\"'))
else:
return u'sudo {}'.format(command.script)